(1/a)-1=(12/a^2)

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Solution for (1/a)-1=(12/a^2) equation: 


D( a )

a^2 = 0

a = 0

a^2 = 0

a^2 = 0

1*a^2 = 0 // : 1

a^2 = 0

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

1/a-1 = 12/(a^2) // - 12/(a^2)

1/a-(12/(a^2))-1 = 0

1/a-12*a^-2-1 = 0

a^-1-12*a^-2-1 = 0

t_1 = a^-1

1*t_1^1-12*t_1^2-1 = 0

t_1-12*t_1^2-1 = 0

DELTA = 1^2-(-12*(-1)*4)

DELTA = -47

DELTA < 0

a belongs to the empty set

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